Travel the 171km from Janakpur to Pokhariya by bus or jeep

Distance171.1 km
Travel Time2.5 - 2.7 hours
Best OptionJeep
Price Range$4 - $22
Alt Change-74m
Last Updated2026

Detailed Route Guide

The route from Janakpur to Pokhariya covers a moderate distance of 171.1 km. It is a classic Nepalese route that bridges two distinct areas of the country. Both locations share a relatively similar elevation (around 0m), meaning you won't experience extreme climate shifts. The weather should remain consistent throughout your trip. Overland transport is your go-to here. Shared jeeps are faster, completing the trip in about 2.5 hours, while buses are the budget-friendly choice.

Tip: Book your tickets at least a day in advance during the peak trekking seasons (Spring and Autumn) to secure the best seats.

Geography Info: Traveling from the Madhesh province to the province.

Let's get you from Janakpur to Pokhariya.

The quickest option is the jeep. You can catch a local Jeep/4WD, which will whisk you across the 171.1 km distance in just 2.5 hours. Keep in mind these jeeps tend to be more expensive than buses, with fares ranging from $12 to $22 USD.

Buses are your budget-friendly alternative. Local buses make multiple trips daily between Janakpur and Pokhariya, taking around 2.7 hours for the journey. Bus prices are significantly lower, starting at $4 USD and going up to $8 USD.

Important Note: Road conditions in Nepal can be unpredictable. While major routes are generally passable, it's always wise to check with local authorities or your accommodation about any potential road closures or advisories before you depart.

Transport Options

TypeDurationPrice (USD)Frequency
Bus2.7 hrs$4 - $8Multiple daily
Jeep2.5 hrs$12 - $22Daily

Where to Stay

Frequently Asked Questions

How long does it take to get from Janakpur to Pokhariya?

It takes between 2.5 and 2.7 hours depending on your chosen transport method.

What is the cheapest way to travel from Janakpur to Pokhariya?

Prices start from $4 USD. Check our detailed guide above for the most economical option.